- ✓$PbO_2$
- B$H_2O_2$
- C$SrO_2$
- D$BaO_2$
$\mathrm{PbO}_{2}$ contains $\mathrm{O}^{2-}$ ions and Option $(\mathrm{A}) \mathrm{Pb}$ is $+4,$ whereas $(\mathrm{B}),(\mathrm{C})$ and (D) contains $[\mathrm{O}-\mathrm{O}]^{2-}$ ions (peroxide ions).
Thus Option A is correct.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,} \\
{C{H_3} - C - CH - CH - CH - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,CHO\,\,}
\end{array}$
is :
$(A)$ $q=0$ $(B)$ $T_2=T_1$ $(C)$ $P_2 V_2=P_1 V_1$ $(D)$ $P_2 V_2^\gamma=P_1 V_1^\gamma$