MCQ
The species which has four unpaired electron is
- A$[Co(CN)_6]^{4-}$
- B$[Cr(H_2O)_6)^{3+}$
- ✓$[FeCl_4]^{2-}$
- D$[Fe(H_2O)_6)^{3+}$
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$4M + 8CN^-+ 2H_2O + O_2 \rightarrow 4[M(CN)_2]^-+ 4OH^-$
$2[M(CN)_2]^-+ Zn \rightarrow [Zn(CN)_4]^{2-} + 2M$
