MCQ
The specific charge of proton is $9.6 \times {10^6}C\,k{g^{ - 1}}$ then for an $\alpha$-particle it will be
  • A
    $38.4 \times {10^7}C\,k{g^{ - 1}}$
  • B
    $19.2 \times {10^7}C\,k{g^{ - 1}}$
  • C
    $2.4 \times {10^7}C\,k{g^{ - 1}}$
  • $4.8 \times {10^7}C\,k{g^{ - 1}}$

Answer

Correct option: D.
$4.8 \times {10^7}C\,k{g^{ - 1}}$
d
(d) ${\left( {\frac{q}{m}} \right)_\alpha } = \frac{1}{2}{\left( {\frac{q}{m}} \right)_p} = \frac{1}{2} \times 9.6 \times {10^7} = 4.8 \times {10^7}C\,k{g^{ - 1}}$

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