MCQ
The specific charge of proton is $9.6 \times {10^6}C\,k{g^{ - 1}}$ then for an $\alpha$-particle it will be
- A$38.4 \times {10^7}C\,k{g^{ - 1}}$
- B$19.2 \times {10^7}C\,k{g^{ - 1}}$
- C$2.4 \times {10^7}C\,k{g^{ - 1}}$
- ✓$4.8 \times {10^7}C\,k{g^{ - 1}}$