Question
The spin-only magnetic moment value for the complex $\left[\mathrm{Co}\left(\mathrm{CN}_{6}\right)\right]^{4-}$ is $......\,BM$ [At. no. of $\mathrm{Co}=27$ ]
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Answer
${\left[\mathrm{CO}(\mathrm{CN})_{6}\right]^{4-}}$
$\mathrm{x}+6 \times(-1)=-4$
$\mathrm{x}=+2$
$\mathrm{Co}^{2+}:[\mathrm{Ar}] 3 \mathrm{~d}^{7}$
and $\mathrm{CN}^{-}$is a strong field ligand which can pair electron of central atom.
It has one unpaired electron ( $n$ ) in $4d-$subshell.So spin only magnetic moment $(\mu)=\sqrt{n(n+2)}\, B . M$
where $\mathrm{n}=$ number of unpaired electrons.
$\mu=\sqrt{3} \,\mathrm{~B} . \mathrm{M} \quad \mu=1.73\, \mathrm{BM}$
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