MCQ
The square root of 64 divided by the cube root of 64 is:
- A$64$
- B$2$
- C$\frac{1}{2}$
- D$64^\frac{2}{3}$
✓
Answer
- $2$
Solution:
We have to find the value of $\frac{\sqrt[2]{64}}{\sqrt[3]{64}}.$
So,
$\frac{\sqrt[2]{64}}{\sqrt[3]{64}}=\frac{\sqrt[2]{2\times2\times2\times2\times2\times2}}{\sqrt[2]{2\times2\times2\times2\times2\times2}}$
$=\frac{2^{6\times\frac{1}{2}}}{2^{6\times\frac{1}{3}}}$
$=\frac{\sqrt[2]{64}}{\sqrt[3]{64}}=\frac{2^3}{2^2}$
$=2^{3-2}$
$=2^1$
$=2$
The value of $\frac{\sqrt[2]{64}}{\sqrt[3]{64}}$ is 2
Hence the correct choice is b.
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