- A[Fe(CO)5]
- B[Fe(CN)6]3–
- C[Fe(C2O4)3]3–
- D[Fe(H2O)6]3+
Explanation:
Chelation (formation of cycle by linkage between metal ion and ligand) stabilizes the coordination compound. The ligand which chelates the metal ion are known as chelating ligand.
Here, only [Fe(C2O4)3]3- is a coordination compound which contains oxalate ion as a chelating ligand. Hence, it stabilizes coordination compound by chelating Fe3+ ion.
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(Nearest integer)
Given, molar mass of $KCl$ is $74.5 g mol ^{-1}$
$(I)\,\, O_3 \to $ product
$(II)\,\,C{r_2}O_7^{ - 2}\xrightarrow{{{H^ + }}}$ product
$(III)\,\,MnO_4^\Theta \xrightarrow{{{H^ + }}}$ product
$(IV)\,\, H_2S \to $ product

Note: py $=$ pyridine
Given: Atomic numbers of $Fe , Co , Ni$ and $Cu$ are $26,27,28$ and $29$ , respectively)
$(A)$ $\left[ FeCl _4\right]^{-}$and $\left[ Fe ( CO )_4\right]^{2-}$
$(B)$ $\left[ Co ( CO )_4\right]^{-}$and $\left[ CoCl _4\right]^{2-}$
$(C)$ $\left[ Ni ( CO )_4\right]$ and $\left[ Ni ( CN )_4\right]^{2-}$
$(D)$ $\left[ Cu ( py )_4\right]^{+}$and $\left[ Cu ( CN )_4\right]^{3-}$
