MCQ
The standard electrode potential $({E^o})$ for $OC{l^ - }/C{l^ - }$ and $C{l^ - }/\frac{1}{2}C{l_2}$ respectively are $0.94\,V$ and $ - 1.36\,V$. The ${E^o}$ value for $OC{l^ - }/\frac{1}{2}C{l_2}$ will be ............... $\mathrm{V}$
  • $ - 0.42$
  • B
    $ - 2.20$
  • C
    $0.52$
  • D
    $1.04$

Answer

Correct option: A.
$ - 0.42$
a
(a)$OC{l^ - } \to {C^ - },\,{E^o} = 0.94\,V$

$C{l^ - } \to \frac{1}{2}C{l_2} + {e^ - }{E^o} = - 1.36\,V$

adding the two equations, we get

$OC{l^ - } \to \frac{1}{2}C{l_2},\,{E^o} = 0.94 - 1.36 = - 0.42\,V$.

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