MCQ
The standard form of $\frac{-48}{60}$ is:
- A$\frac{48}{60}$
- B$\frac{-601}{48}$
- ✓$\frac{-4}{5}$
- D$\frac{-4}{-5}$
Given rational number is $\frac{-48}{60}.$
For standrad/ simplest form, divide numerator and denomin by their $HCF$
i.e. $\frac{-48+12}{60+12}=\frac{-4}{5}$
Hence, the standard form of $\frac{-48}{60}$ is $\frac{-4}{5}.$
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