MCQ
The standard reduction potential for the half reactions are as $Zn = Z{n^{2 + }} + 2{e^ - };\,\,{E^o} = + 0.76\,V$ $Fe = F{e^{2 + }} + 2{e^ - };\,\,{E^o} = + 0.41\,V$ The $EMF$ for cell reaction $F{e^{2 + }} + Zn\, \to \,Z{n^{2 + }} + Fe$ is ............ $\mathrm{V}$
- A$ - 0.35$
- ✓$ + 0.35$
- C$ + 1.17$
- D$ - 1.17$
