MCQ
The starting substance for the preparation of $C{H_3}I$ is
- ✓$C{H_3}OH$
- B${C_2}{H_5}OH$
- C$C{H_3}CHO$
- D${(C{H_3})_2}CO$
✓
Answer
Correct option: A.
$C{H_3}OH$
a
(a)$C{H_3}OH + HI\xrightarrow{{ZnC{l_2}}}C{H_3}I + {H_2}O$
(a)$C{H_3}OH + HI\xrightarrow{{ZnC{l_2}}}C{H_3}I + {H_2}O$
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