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6.2. Equilibrium - II (icon Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.2. Equilibrium - II (icon Equilibrium)1 Mark
MCQ
The stoichiometry and solubility product of a salt with the solubility curve given below is, respectively
  • A
    $\mathrm{X}_{2} \mathrm{Y}, 2 \times 10^{-9} \;\mathrm{M}^{3}$
  • B
    $\mathrm{XY}_{2}, 1 \times 10^{-9} \;\mathrm{M}^{3}$
  • ✓
    $\mathrm{XY}_{2}, 4 \times 10^{-9}\; \mathrm{M}^{3}$
  • D
    $\mathrm{XY}, 2 \times 10^{-6} \;\mathrm{M}^{3}$
✓

Answer

Correct option: C.
$\mathrm{XY}_{2}, 4 \times 10^{-9}\; \mathrm{M}^{3}$
c
From the graph and dimensions salt is : $\mathrm{XY}_{2}$

$[\mathrm{X}]=1 \times 10^{-3} \mathrm{M}$

$[\mathrm{Y}]=2 \times 10^{-3} \mathrm{M}$

$\mathrm{XY}_{2}(\mathrm{s}) \rightleftharpoons \mathrm{X}_{(\mathrm{aq}, )}^{2+}+2 \mathrm{Y}_{(\mathrm{aq})}^{-}$

$\mathrm{K_{sp}}=\left[\mathrm{X}^{2+}\right][\mathrm{Y}^-]^{2}$

$=\left(10^{-3}\right)\left(2 \times 10^{-3}\right)^{2}$

$=4 \times 10^{-9} \mathrm{M}^{3}$

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