The straight line y = mx + c cuts the circle x^2+ y^2= a^2 in rea… - Vidyadip

MCQ

The straight line $y = mx + c$ cuts the circle $x^2+ y^2= a^2$ in real points if:

A
$\sqrt{{\text{a}^2 × (1 + \text{m}^2)} < \text{c}}$
B
$\sqrt{{\text{a}^2 × (1 - \text{m}^2)} < \text{c}}$
✓
$\sqrt{{\text{a}^2 × (1 + \text{m}^2)} > \text{c}}$
D
$\sqrt{{\text{a}^2 × (1 - \text{m}^2)} > \text{c}}$

✓

Answer

Correct option: C.

$\sqrt{{\text{a}^2 × (1 + \text{m}^2)} > \text{c}}$

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