MCQ
The string of a violin emits a note of $205 \,Hz$ at its correct tension. The string is tightened slightly and then it produces six beats in two seconds with a tuning fork of frequency $205 Hz$. The frequency of the note emitted by the taut string is .......... $Hz$ 
  • A
    $211$
  • B
    $199$
  • $208$
  • D
    $202$

Answer

Correct option: C.
$208$
c
(c)

Initial frequency $=205 \,Hz$

String tightned so frequency is increased $=205+f$

Final frequency of string $-$ frequency of tuning fork $=3$ beats

$205+f-205=3$

$\therefore f=3$

$\therefore$ Final frequency $=205+3=208 \,Hz$

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