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4. Chemical bonding and molecular structure — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry4. Chemical bonding and molecular structure1 Mark
MCQ
The structural formula of a compound is $C{H_3} - CH = C = C{H_2}.$ The type of hybridization at the four carbons from left to right are
  • A
    $s{p^2},\,\,sp,\,\,s{p^2},\,\,s{p^3}$
  • B
    $s{p^2},\,\,s{p^3},\,\,s{p^2},\,\,sp$
  • ✓
    $s{p^3},\,\,s{p^2},\,\,sp,\,\,s{p^2}$
  • D
    $s{p^3},\,\,s{p^2},\,\,s{p^2},\,\,s{p^2}$
✓

Answer

Correct option: C.
$s{p^3},\,\,s{p^2},\,\,sp,\,\,s{p^2}$
c
The hybridization of carbon in any compound is based on the no. of pi bonds attached to the given carbon. If carbon has only sigma bonds, then hybridization is $sp ^3$, if carbon forms one pi bond, then $sp ^2$ hybridized, and if carbon forms $2$ pi bonds, then, it is $sp$ hybridized.

Hence the correct order is $sp ^3, sp ^2, sp ^2, sp ^2$

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