The sum of 1^3 + 2^3 + 3^3 + 4^3 + ..... + 15^3 , is - Vidyadip

Question

The sum of ${1^3} + {2^3} + {3^3} + {4^3} + ..... + {15^3}$, is

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Answer

c
(c) Sum of cubes of $'n'$ natural number

$ = \frac{{{n^2}{{(n + 1)}^2}}}{4} = \frac{{{{15}^2}{{(16)}^2}}}{4} = 14,400$.

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