Question
The sum of first n odd natural numbers is $n^2$.
✓
Answer
True.
Solution:
Sum of odd natural numbers $=\sum(2\text{n}-1)=\frac{2\times\text{n}\times(\text{n}+1)}{2}-2$ $=\text{n}^2+\text{n}-\text{n}=\text{n}^2$
Solution:
Sum of odd natural numbers $=\sum(2\text{n}-1)=\frac{2\times\text{n}\times(\text{n}+1)}{2}-2$ $=\text{n}^2+\text{n}-\text{n}=\text{n}^2$
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