MCQ
The sum of rational and an irrational number:
- ARepeating number.
- BIs always irrational.
- CIs always rational.
- DFraction number.
✓
Answer
- Is always irrational.
Solution:
By definition, an irrational number in decimal form goes on forever without repeating (a non-repeating, non-terminating decimal). By definition, a rational number in the decimal form either terminates or repeats. If you add a non-repeating, non-terminating decimal to a terminating decimal, you still have a non-repeating, non-terminating decimal. If you add a non-repeating,
Non-terminating decimal to a repeating decimal, you will no longer have a repeating decimal.
$3+\sqrt{5}=3+2.236067977=5.236067977$ which is irreational.
$4\frac{1}{3}+\pi=4.33333333+3.141592653= 4.47925986$ which is also irrational
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In a $\triangle\text{ABC},$ If $\angle\text{A}= 45^\circ$ and $\angle\text{B}= 70^\circ.$ Determine the shortest sides of the triangles.
→The value of 'a' for which (x + a) is a factor of the polynomial x3 + ax2 + a + 6 is:
A chord is at a distance of 8cm from the centre of a circle of radius 17cm. The length of the chord is:
The volume of a cone is 1570cm2. If it is 15cm high, then its base area is:
In the following, write the correct answer.
D is point on the side BC of a $\triangle\text{ABC}$ such that AD bisects Then.
→D is point on the side BC of a $\triangle\text{ABC}$ such that AD bisects Then.
$(125)^{-\frac{1}{3}}=?$
→- 5
- -5
- $\frac{1}{5}$
- $-\frac{1}{5}$
If $\frac{\text{a}}{\text{b}}+\frac{\text{b}}{\text{a}}=1,$ then a3 + b3 =
→The simplest rationalising factor of $2 \sqrt{5}-\sqrt{3}$, is
→Write the correct answer in the following:
D and E are the mid-points of the sides AB and AC of $\Delta\text{ABC}$ and O is any point on side BC. O is joined to A. If P and Q are the mid-points of OB and OC respectively, then DEQP is:
→D and E are the mid-points of the sides AB and AC of $\Delta\text{ABC}$ and O is any point on side BC. O is joined to A. If P and Q are the mid-points of OB and OC respectively, then DEQP is: