Question
The surface area of a sphere is $5544 \mathrm{~cm}^2$, find its diameter.
✓
Answer
Surface area of a sphere is $5544 \mathrm{~cm}^2$
$4\pi\text{r}^2=5544$
$4\times3.14\times(\text{r})^2=5544$
$\text{r}^2=\frac{5544\times7}{88}$
$\text{r}=\sqrt{21\text{cm}\times21\text{cm}}$
$\text{r}=21\text{cm}$ Diameter $= 2$(radius) $= 2(21) = 42cm$
$4\pi\text{r}^2=5544$
$4\times3.14\times(\text{r})^2=5544$
$\text{r}^2=\frac{5544\times7}{88}$
$\text{r}=\sqrt{21\text{cm}\times21\text{cm}}$
$\text{r}=21\text{cm}$ Diameter $= 2$(radius) $= 2(21) = 42cm$
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