The system x - 2y = 3 and 3x + ky = 1 has a unique solution only … - Vidyadip

MCQ

The system $x - 2y = 3$ and $3x + ky = 1$ has a unique solution only when:

A
$\text{k}=-6,$
✓
$\text{k}\neq-6$
C
$\text{k}=0$
D
$\text{k}\neq0$

✓

Answer

Correct option: B.

$\text{k}\neq-6$

$x - 2y = 3$ and $3x + ky = 1$
We know that,
the system of linear equations $a_1x + b_1x + c_1 = 0, a_2x + b_2y + c_2 = 0$ has a unique solution if $\frac{\text{a}_1}{\text{a}_2}\neq\frac{\text{b}_1}{\text{b}_2}.$
So, $\frac{1}{3}\neq\frac{-2}{\text{k}}$
$\Rightarrow\text{k}\neq-6.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Linear Equation In Two Variable→Linear Equation In Two Variable — all question types→Maths STD 10 question papers→Maharashtra Board STD 10 question papers→Maharashtra Board question paper generator→

Similar questions

If $35$ is removed from the data : $30, 34, 35, 36, 37, 38, 39, 40,$ then the median increases by:

$\triangle\text{ABC}\sim\triangle\text{PQR}$ such that $\text{ar}(\triangle\text{ABC})=4\ \text{ar}(\triangle\text{PQR}).$ If $\text{BC} = 12\ cm,$ then $\text{QR} =$

Some questions and their alternative answers are given. Select the correct alternative.
Out of the dates given below which date constitutes a Pythagorean triplet?

While computing mean of grouped data, we assume that the frequencies are:

For an given A.P. a = 3.5, d = 0, n = 101, then t_n = . . .

The number of decimal places after which the decimal expansion of the rational number $\frac{23}{2^2\times5}$ will terminate, is:

Which of the following is a polynomial?

In the formula $\bar{\text{x}}=\text{a}+\text{h}\Big(\frac{1}{\text{N}}\sum\text{f}_\text{i}\text{u}_\text{i}\Big),$ for finding the mean of grouped frequency distribution $\text{u}_\text{i}=$

If one root of the equation $3x^2- 10x + 3 = 0$ is $\frac{1}{3}$ then the other root is:

If $x = 1$ is a common roots of the equations $ax^2 + ax + 3 = 0$ and $x^2 + x + b = 0$, then $ab =$