MCQ
The system $x - 2y = 3$ and $3x + ky = 1$ has a unique solution only when :
- ✓$k \neq -6$
- B$k = 0$
- C$k = - 6$
- D$k \neq 0$
✓
Answer
Correct option: A.
$k \neq -6$
For a unique solution,
we have $\frac{\text{a}_{1}}{\text{a}_{2}}\neq\frac{\text{b}_{1}}{\text{b}_{2}}$
So $\frac{1}{3}\neq\frac{-2}{\text{k}}$
$\Rightarrow \text{k}\neq-6$
we have $\frac{\text{a}_{1}}{\text{a}_{2}}\neq\frac{\text{b}_{1}}{\text{b}_{2}}$
So $\frac{1}{3}\neq\frac{-2}{\text{k}}$
$\Rightarrow \text{k}\neq-6$
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