- A$3-$ hydroxy $-2-$ bromopropane
- ✓$2-$ bromopropanol $-1$ ol
- C$2-$ bromo $-3-$ propanol
- D$3-$ hydroxy isopropyl bromide
Suffix used for $-OH$ functional group is $ol$.
Halogens are always used as substituent.
$\begin{matrix} {{H}_{3}}C-CH-C{{H}_{2}}-OH \\ |\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\ Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\ \end{matrix}$
Thus, the $IUPAC$ name of given compound is $2$-bromopropan-$1$-ol
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$CO(g) + Cl_2(g) \rightleftharpoons COCl_2(g)$
The reaction carried out in a $500\,mL$ flask. At equilibrium, $0.3\,mol$ of phosgene, $0.1\, mol$ of $CO,$ and $0.1\,mol$ of $Cl_2$ are present. The equilibrium constant of the reaction is
$\begin{array}{*{20}{l}}
{(u){H_2}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} CHC{H_3}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} (v){\mkern 1mu} C{H_2}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} CHCl{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} (w){\mkern 1mu} C{H_3}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} H_2^ + {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} (x){\mkern 1mu} H - C \equiv C - H} \\
{(y){\mkern 1mu} C{H_3}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} N{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} (z){\mkern 1mu} {{(C{H_3})}_2}C\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{N} N{H_2}}
\end{array}$

${H_2}O + {H_2}PO^-_4 \rightleftharpoons {H_3}{O^ + } + HPO_4^{ - 2}$
Select out the group of acidic species lying on the right side of the equilibrium