MCQ
The tautorner of $II$ is


- A$I$
- B$III$
- ✓both $I$ and $III$
- Dnone of these


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${C_({graphite)}} + {O_2} \to C{O_2};\,\Delta H = - 393.4\,kJ/mole$
${C_({graphite})} \to {C_{{\rm({diamond})}}};\,\Delta H = $

Under standard conditions, the number of moles of $M ^{+}$oxidized when one mole of $X$ is converted to $Y$ is $\left[ F =96500 \ C \ mol ^{-1}\right]$
