The tension of a wire is 2.5 kg. When the load increase its frequency changes to 3: 2. Find the original stress.
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Answer
Let original stress is T. $n=\frac{1}{2 l} \sqrt{\frac{T}{m}}\ldots\ldots (1)$ To increase 2.5 kilogram then frequency is equal to $\frac{3}{2} n .$ $\frac{3}{2} n=\frac{1}{2 l} \sqrt{\frac{T+2.5}{m}}\ldots\ldots (2)$ Divide equation (1) and (2) $\Rightarrow \frac{2}{3}=\sqrt{\frac{T}{T+2.5}}$ Taking square both side $\frac{4}{9}=\frac{T}{T+2.5}$ $4 T+10=9 T$ $10=9 T-4 T$ $5T=10$ $T=\frac{10}{5}=2 kg \cdot w t$.
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