Question
The tenth elements in the periodic table resembles with the

Answer

b
$(b)$ Each period consists of a series of elements whose atom have the same principal quantum no. $(n)$ of the outer most shell i.e. In second period $n = 2$, this shell has four orbitals (one $2s$ and three $2p$) which can have eight electrons, hence second period contains $8$ elements from atomic no. $3$ to $10.$

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