MCQ
The total energy of the electron of $H-$ atom in the second quantum state is $-E_2$. The total energy of the $He^+$ atom in the third quantum state is
- A$ - \frac{3}{2}{E_2}$
- B$ - \frac{2}{3}{E_2}$
- C$ - \frac{16}{9}{E_2}$
- ✓$ - \frac{4}{9}{E_2}$