MCQ
The total magnetic quantum numbers for $d$-orbital is given by
- A$2$
- B$0$,$ \pm 1$,$ \pm 2$
- C$0, 1, 2$
- ✓$5$
✓
Answer
Correct option: D.
$5$
d
(d) $m = (2l + 1)$ for d orbital $l = 2$$m = (2 \times 2 + 1) = 5$.
(d) $m = (2l + 1)$ for d orbital $l = 2$$m = (2 \times 2 + 1) = 5$.
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