MCQ
The total number of electrons present in all the $s-$ orbitals, all the $p-$ orbitals and all the $d-$ orbitals of cesium ion are respectively
- A$8, 26, 10$
- ✓$10, 24, 20$
- C$8, 22, 24$
- D$12, 20, 22$
✓
Answer
Correct option: B.
$10, 24, 20$
b
(b) $(Cs{\,_{35}})\, = \,1{s^2},\,2{s^2},\,\,2{p^6},3{s^2},3{p^6},3{d^{10}},4{s^2}$
(b) $(Cs{\,_{35}})\, = \,1{s^2},\,2{s^2},\,\,2{p^6},3{s^2},3{p^6},3{d^{10}},4{s^2}$
$4{p^6},4{d^{10}},5{s^2},5{p^6},6{s^1}$
$C{s^ + } = 1{s^2},\,2{s^2},2{p^6},\,3{s^2},3{p^6},3{d^{10}},\,4{s^2}$,
$4{p^6},4{d^{10}},\,5{s^2},5{p^6}$
Total no. of ${e^ - }$ in $s-$ orbitals $ = 10$
Total no. of ${e^ - }$ in $p-$ ortbitals $ = 24$
Total no. of ${e^ - }$ in $d-$ ortbitals $ = 20$
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