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Product $X$ is

$6CO_2 + 6H_2O + solar energy \to C_6H_{12}O_6+6O_2$
A blue whales gain $75\ kg$ of mass per day by feeding on krill. The whale must consume ten times this mass of krill each day. The krill must consume $10.0\ kg$ of diatoms to produce $1.0\ kg$ of krill. Assuming that the mass gain of a whale's life is due to the consumption of carbohydrates $(C_6H_{12}O_6)$ , calculate the moles of $CO_2$ that must be used by the diatoms to produce the carbohydrates consumed by a blue whale in a day

For the cell $\mathrm{Cu}(\mathrm{s})\left|\mathrm{Cu}^{2+}(\mathrm{aq})(0.01 \mathrm{M}) \| \mathrm{Ag}^{+}(\mathrm{aq})(0.001 \mathrm{M})\right| \mathrm{Ag}(\mathrm{s})$ the cell potential $=.....\times 10^{-2} \mathrm{~V}$
(Round off to the Nearest Integer).
[Use: $\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059$ ]