MCQ
The transverse displacement of a string (clamped at its both ends) is given by $\text{y}(\text{x, t})=0.06\sin(1\pi\text{x/ 3})\cos(120\pi\text{t}).$
All the points on the string between two consecutive nodes vibrate with
  • A
    Same frequency.
  • B
    Same phase.
  • C
    Different amplitude.
  • All of the above

Answer

Correct option: D.
All of the above
The frequencies of all particles are same, verifies the option $(a).$
particles between any two consecutive nodes vibrates either upside or downside having sameb phase $120\pi\text{t}$ ay atime, verifies the option $(b)$
particles have ditternt energies. so rejects the option $(c)$
As the amplitude of different particles are diffrent between two nodes energy $(E) \propto\text{A}^2.$ 

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