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Chemical Thermodynamics — Chemistry STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 ScienceChemistryChemical Thermodynamics1 Mark
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Answer

Correct option: B.
both $\Delta S$ and S are functions of temperature
(b) : According to third law of thermodynamics,$\Delta S=S_T-S_0=\int_0^T \frac{C_P d T}{T}=C_p \ln T=2.303 C_P \log T$
Where $S_T$ and $S_0$ are entropies at $T K$ and $0 K$ respectively.
As, $S_0=0$ (According to third law),
$\therefore \quad S=\int_0^T \frac{C_P d T}{T}$

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