The Truth table for the given logic circuit is: - Vidyadip

MCQ

The Truth table for the given logic circuit is:

A

$A$ $B$ $C$

$0$ $1$ $0$

$0$ $1$ $0$

$1$ $0$ $0$

$1$ $1$ $1$
✓

$A$ $B$ $C$

$0$ $0$ $1$

$0$ $1$ $0$

$1$ $0$ $1$

$1$ $1$ $0$
C

$A$ $B$ $C$

$0$ $0$ $0$

$0$ $1$ $0$

$1$ $0$ $0$

$1$ $1$ $1$
D

$A$ $B$ $C$

$0$ $0$ $0$

$0$ $1$ $1$

$1$ $0$ $1$

$1$ $1$ $0$

✓

Answer

Correct option: B.

$A$	$B$	$C$
$0$	$0$	$1$
$0$	$1$	$0$
$1$	$0$	$1$
$1$	$1$	$0$

b
$C=\overline{A \cdot B} \cdot \bar{A} \cdot B$

using De-Morgan Theorem

$C=\overline{A \cdot B+\bar{A} \cdot B}$

$C=\overline{B(A+\bar{A})}=\bar{B}$

Therefore

$A$	$B$	$C$
$0$	$0$	$1$
$0$	$1$	$0$
$1$	$0$	$1$
$1$	$1$	$0$

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