- ✓${m^3}$
- B$c{m^3}$
- C$d{m^3}$
- DNone of these
Dimension of Joule i.e. work $ = F \times L$ $ = ML{T^{ - 2}} \times L$
$ = \left[ {M{L^2}{T^{ - 2}}} \right]$
$\frac{1}{{Pa}} = \frac{1}{{{\rm{Pressure}}}} = \frac{1}{{\frac{F}{A}}} = \frac{{1 \times A}}{F} = \left[ {ML{T^{ - 1}}} \right]$
So, $J \,P{a^{ - 1}}$ $ = \left[ {M{L^2}{T^2}} \right]$ $ = \left[ {{L^2} \times L} \right]\; = \left[ {{L^3}} \right]$.
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$\mathrm{MnO}_{4}^{-}+\mathrm{C}_{2} \mathrm{O}_{4}^{2-}+\mathrm{H}^{+} \longrightarrow \mathrm{Mn}^{2+}+\mathrm{CO}_{2}+\mathrm{H}_{2} \mathrm{O}$
the correct coefficients of the reactants for the balanced equation are
$\mathrm{MnO}_{4}^{-} \quad \mathrm{C}_{2} \mathrm{O}_{4}^{2-}\quad \mathrm{H}^{+}$
