MCQ
The unit of electric permittivity is
- A$Volt/m^2$
- B$Joule/coulomb$
- ✓$Farad/m$
- D$Henry/m$
✓
Answer
Correct option: C.
$Farad/m$
c
(c) $C = \frac{{{\varepsilon _0}A}}{d}$ $⇒$ ${\varepsilon _0} = \frac{{Cd}}{A}$ $⇒$ ${\varepsilon _0}$ $⇒$ $\frac{{Farad \times m}}{{{m^2}}} \to \frac{F}{m}$
(c) $C = \frac{{{\varepsilon _0}A}}{d}$ $⇒$ ${\varepsilon _0} = \frac{{Cd}}{A}$ $⇒$ ${\varepsilon _0}$ $⇒$ $\frac{{Farad \times m}}{{{m^2}}} \to \frac{F}{m}$
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