MCQ
The unit vector perpendicular to both $i + j$ and $j + k$ is
- A$i -j + k$
- B$i + j + k$
- C$\frac{{i + j - k}}{{\sqrt 3 }}$
- ✓$\frac{{i - j + k}}{{\sqrt 3 }}$
$ = \frac{{(i + j) \times (j + k)}}{{|(i + j) \times (j + k)|}} = \frac{{i - j + k}}{{\sqrt 3 }}$.
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$(I)$ The curve $y=f(x)$ intersects the $x$-axis exactly at one point
$(II)$ The curve $y=f(x)$ intersects the $x$-axis at $\mathrm{x}=\cos \frac{\pi}{12}$
Then