MCQ
The unit vector perpendicular to the vectors $i - j + k$ and $2i + 3j - k$ is
  • A
    $\frac{-2i+3j+5k}{\sqrt{30}}$
  • B
    $\frac{{ - 2i + 5j + 6k}}{{\sqrt {38} }}$
  • $\frac{{ - 2i + 3j + 5k}}{{\sqrt {38} }}$
  • D
    $\frac{-2i+4j+5k}{\sqrt{38}}$

Answer

Correct option: C.
$\frac{{ - 2i + 3j + 5k}}{{\sqrt {38} }}$
c
(c) Vectors $a = i - j + k$ and $b = 2i + 3j - k$.

We know that$a \times b = i(1 - 3) - j( - 1 - 2) + k(3 + 2)$
$ = - \,2i + 3j + 5k$

and $|a \times b|\,$$ = \sqrt {{{( - 2)}^2} + {{(3)}^2} + {{(5)}^2}} = \sqrt {38} $

Therefore unit vector $\frac{{a \times b}}{{|a \times b|}} = \frac{{ - 2i + 3j + 5k}}{{\sqrt {38} }}$.

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