MCQ
The $UPAC$ name of the compound $C{H_2} = CH - C{H_2} - C{H_2} - C \equiv CH$ is
- A$1, 5-$hexenyne
- B$1-$hexyne$-5-$ene
- C$1, 5-$hexynene
- ✓$1-$hexene$-5-$yne
So, the IUPAC name of the given formula is hex-$1$-en-$5$-yne or $1$-hexene-$5$-yne.
$\stackrel{1}{ CH _2}=\stackrel{2}{ CH }-\stackrel{3}{ CH _2}-\stackrel{4}{ C } H _2-\stackrel{5}{ C } \equiv \stackrel{6}{ CH }$
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$I :$ The three elements are metals.
$II :$ The electro negativities decrease from $X$ to $Y$ to $Z$.
$III :$ The atomic radius decreases in the order $X, Y$ and $Z.$
$IV : X, Y$ and $Z$ could be phosphorus, aluminium and sodium respectively.