The upper end of a wire $1\,m$ long and $4\,mm$ radius is clamped. The lower end is twisted by an angle of $30^o$. The angle of shear is ...... $^o$
Diffcult
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$\mathrm{BB}^{\prime}=\mathrm{r} \theta=\mathrm{L} \phi$
$\phi=$ Angle of shear
$\theta \therefore$ Angle of twist
$\phi=\frac{r \theta}{L}=\frac{0.4 \times 30^{\circ}}{100}=0.12^{\circ}$
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