Question
The usual form for $2 × 10^{-2}$ is not equal to $0.02.$

Answer

False.Solution:
For usual form, $2\times10^{-2}=2\times\frac{1}{10^2}$ $\Big[\because\text{a}^{-\text{m}}=\frac{1}{\text{a}^\text{m}}\Big]$ $=\frac{2}{100}=0.02$

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