The value of (1 + i)^5 (1 - i)^5 is - Vidyadip

Question

The value of ${(1 + i)^5} \times {(1 - i)^5}$ is

✓

Answer

d
(d) ${(1 + i)^5}{(1 - i)^5} = {(1 - {i^2})^5} = {2^5} = 32$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The sum of the maximum and minimum values of the function $f(x)=|5 x-7|+\left[x^{2}+2 x\right]$ is the interval $\left[\frac{5}{4}, 2\right]$, where $[ t ]$ is the greatest integer $\leq t$ is $.......$

Four dice (six faced) are rolled. The number of possible outcomes in which at least one die shows $2$ is

Let the domain of the function $f(x)=\log _{4}\left(\log _{5}\left(\log _{3}\left(18 x-x^{2}-77\right)\right)\right)$ be $(a, b)$. Then the value of the integral $\int_{a}^{b} \frac{\sin ^{3} x}{\left(\sin ^{3} x+\sin ^{3}(a+b-x)\right)} d x$ is equal to $.....$

$\int\limits_{\frac{1}{2}}^2 {\frac{1}{x}\,\sin \left( {x - \frac{1}{x}} \right)\,\,\,dx} $ has the value equal to

Let the complex numbers $\alpha$ and $\frac{1}{\bar{\alpha}}$ lie on the circles $\left|z-z_0\right|^2=4$ and $z-\left.z_0\right|^2=16$ respectively, where $z_0=1+i$. Then, the value of $100|\alpha|^2$ is.

If $P \equiv (x,\;y)$, ${F_1} \equiv (3,\;0)$, ${F_2} \equiv ( - 3,\;0)$ and $16{x^2} + 25{y^2} = 400$, then $P{F_1} + P{F_2}$ equals

Number of integral tems in the expansion of $\left\{7^{\left(\frac{1}{2}\right)}+11^{\left(\frac{1}{6}\right)}\right\}^{824}$ is equal to..................

$A\,\,5$-digit number $\overline{a b c d e}$, when multiplied by $9$ , gives the $5-$digit number $edcba.$ The sum of the digits in the number is

For $\mathrm{a}, \mathrm{b}>0$, let $f(x)=\left\{\begin{array}{l}\frac{\tan ((a+1) x)+b \tan x}{x}, x<0 \\ \frac{\sqrt{a x+b^2 x^2}-\sqrt{a x}}{b \sqrt{a} x \sqrt{x}}, x>0\end{array}\right.$ be a continous function at $x=0$. Then $\frac{b}{a}$ is equal to

The minimum value of ${\left( {\frac{3}{a} - 1} \right)^2} + {\left( {\frac{a}{b} - 1} \right)^2} + {\left( {\frac{b}{c} - 1} \right)^2} + {\left( {3c - 1} \right)^2}$ where $0\, < a,\,b,\,c\, \leqslant \,9$ ,is $p - q\sqrt r $ ; $p,q,r \in I$ and $q$ , $r$ are coprimes, then $(p + q + r)$ is equal to