MCQ
The value of $\frac{(2.3)^3-0.027}{(2.3)^2+0.69+0.09},$ is:
- ✓$2$
- B$3$
- C$2.327$
- D$2.273$
✓
Answer
Correct option: A.
$2$
$\frac{(2.3)^3-0.027}{(2.3)^2+0.69+0.09}$
$=\frac{(2.3)^3-(0.3)^3}{(2.3)^2+(0.3)^3+(2.3)(0.3)}$
$=\frac{(2.3 - 0.3)\{(2.3)^2+(0.3)^2+(2.3)(0.3)\}}{((2.3)^2+(0.3)^2+(2.3)(0.3))}$
$=2.3 - 0.3$
$=2$
Hence, correct option is $(a).$
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