Question
The value of $(249)^2 - (248)^2$ is:
✓
Answer
$(249)^2 - (248)^2$
$= (249 + 248) (249 - 248) [$Using identity $a^2 - b^2 = (a + b) (a - b)]$
$= 497 \times 1$
$= 497$
$= (249 + 248) (249 - 248) [$Using identity $a^2 - b^2 = (a + b) (a - b)]$
$= 497 \times 1$
$= 497$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In the following, write the correct answer.
If AB = QR, BC = PR and CA = PQ, then:
If AB = QR, BC = PR and CA = PQ, then:
The radii of the bases of a cylinder and a cone are in the ratio 3 : 4 and their heights are in the ratio 2 : 3. Then, their volumes are in the ratio:
Write the correct answer in the following: Degree of the polynomial $4x^4 + 0x^3 + 0x^5 + 5x + 7$ is.
→If $\text{x}=2+\sqrt{3}$ then $\Big(\text{x}+\frac{1}{\text{x}}\Big)$ equals:
→- $-2{\sqrt{3}}$
- 2
- 4
- $4-2\sqrt{3}$
The perpendicular distance of the point P(4, 3) from y-axis is:
- 4
- 3
- 5
- None of these
In a circle with centre O, AB and CD are two diameters perpendicular to each other. The length of chord AC is:
→→- $2\text{AB}$
- $\sqrt{2}$
- $\frac{1}{2}\text{AB}$
- $\frac{1}{\sqrt{2}}\text{AB}$
Tally marks are used to find:
A right circular cylinder and a right circular cone have the same radius and the same volume. The ratio of the height of the cylinder to that of the cone is:
The value of $x - y^{x-y}$ when $x = 2$ and $y = -2$ is:
→