Gujarat BoardEnglish MediumSTD 8MATHSExponents and Powers1 Mark
Question
The value of $\left[3^{-1} \times 4^{-1}\right]^2$ is _________.
✓
Answer
The value of $\left[3^{-1} \times 4^{-1}\right]^2$ Is $\frac{1}{144}$. Solution:
Using law of exponents, $\text{a}^{-\text{m}}=\frac{1}{\text{a}^\text{m}}$ [$\because$ a is non-zero integer]
$\therefore$ $\big[3^{-1}\times4^{-1}\big]^2=\Big(\frac{1}{3}\times\frac{1}{4}\Big)^2=\Big(\frac{1}{12}\Big)^2$
$=12^{-2}=\frac{1}{144}$
Hence,
$\big[3^{-1}\times4^{-1}\big]^2=\frac{1}{144}$
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