MCQ
The value of $\left(3 x^3+9 x^2+27 x\right) \div 3 x$ is:
- A$x^2+9+27 x$
- B$3 x^3+3 x^2+27 x$
- C$3 x^3+9 x^2+9$
- ✓$x^2+3 x+9$
✓
Answer
Correct option: D.
$x^2+3 x+9$
D. $x^2+3 x+9$
Solution:
$(3\text{x}^2+9\text{x}^2+27\text{x})$
$=\frac{3\text{x}^3+9\text{x}^2+27\text{x}}{3\text{x}}$
$=\frac{3\text{x}^3}{3\text{x}}+\frac{9\text{x}^2}{3\text{x}}+\frac{27\text{x}}{3\text{x}}$
$=\text{x}^2+3\text{x}+9$
Solution:
$(3\text{x}^2+9\text{x}^2+27\text{x})$
$=\frac{3\text{x}^3+9\text{x}^2+27\text{x}}{3\text{x}}$
$=\frac{3\text{x}^3}{3\text{x}}+\frac{9\text{x}^2}{3\text{x}}+\frac{27\text{x}}{3\text{x}}$
$=\text{x}^2+3\text{x}+9$
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