MCQ
The value of ${}^{50}{C_4} + \sum\limits_{r = 1}^6 {^{56 - r}{C_3}} $ is
- A$^{56}{C_3}$
- ✓$^{56}{C_4}$
- C$^{55}{C_4}$
- D$^{55}{C_3}$
Taking first two terms together and adding them and following the same pattern, we get${\,^{56}}{C_4}$, $[As\,{\,^n}{C_r} + {\,^n}{C_{r - 1}} = {\,^{n + 1}}{C_r}]$.
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