MCQ
The value of $\Big(-\frac{2}{3}\Big)^4$ is equal to:
  • $\frac{16}{81}$
  • B
    $\frac{81}{16}$
  • C
    $\frac{-16}{81}$
  • D
    $\frac{81}{-16}$

Answer

Correct option: A.
$\frac{16}{81}$
A.  $\frac{16}{81}$
Solution:
Given,
$\Big(\frac{-2}{3}\Big)^4$
$=\Big(\frac{-2}{3}\Big)\times\Big(\frac{-2}{3}\Big)\times\Big(\frac{-2}{3}\Big)\times\Big(\frac{-2}{3}\Big)$
$=\frac{16}{81}$
[for $(-a)^m,$ if m is even, then $(-a)^m$ is positive]

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