Question
The value of $\Big(\frac{1}{2^3}\Big)^3$ is equal to _________.

Answer

The value of $\Big(\frac{1}{2^3}\Big)^2$ is equal to $\frac{1}{2^6}$.
Solution:
Using law of exponents, $(am)n = (a)mn [$$\because$ a is non-zero integer$]$
$\because$ $\Big(\frac{1}{2^3}\Big)^2=\Big(\frac{1^3}{2^3}\Big)^2=\Big(\frac{1}{2}\Big)^{3\times2}$
$=\Big(\frac{1}{2}\Big)^6=\frac{1}{2^6}$ [$\because$ $(1)^m= 1]$
Hence,
$\Big(\frac{1}{2^3}\Big)^2$ = $\frac{1}{2^6}$

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