MCQ
The value of $\cos ^2 \theta+\frac{1}{1+\cot ^2 \theta}$ is
- A$0$
- ✓1
- C2
- D-1
✓
Answer
Correct option: B.
1
(B)1
$\cos ^2 \theta+\frac{1}{1+\cot ^2 \theta}=\cos ^2 \theta+\frac{1}{\operatorname{cosec}^2 \theta}=\cos ^2 \theta+\sin ^2 \theta=1$
$\cos ^2 \theta+\frac{1}{1+\cot ^2 \theta}=\cos ^2 \theta+\frac{1}{\operatorname{cosec}^2 \theta}=\cos ^2 \theta+\sin ^2 \theta=1$
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