MCQ
The value of  $\cot \left( {\sum\limits_{r = 1}^\infty  {{{\tan }^{ - 1}}\left( {\frac{4}{{4{r^2} + 3}}} \right)} } \right)$ is equal to
  • A
    $1$
  • $\frac{1}{2}$
  • C
    $2$
  • D
    $\frac{1}{4}$

Answer

Correct option: B.
$\frac{1}{2}$
b
$\tan ^{-1}\left(\frac{4}{4 r^{2}+3}\right)=\tan ^{-1}\left(r+\frac{1}{2}\right)-\tan ^{-1}\left(r-\frac{1}{2}\right)$

$\sum\limits_{r = 1}^n {{{\tan }^{ - 1}}\left( {\frac{4}{{4{r^2} + 3}}} \right)}  = {\cot ^{ - 1}}\left( {\frac{1}{2}} \right)$

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