MCQ
The value of current through $20\,\Omega $ resistor is .................. $A$


- A$1.2$
- B$0.3$
- ✓$0.6$
- D$1.8$

$\frac{x-10}{10}+\frac{x+6}{20}+\frac{x}{10}+\frac{x-10}{5}=0$
$\Rightarrow \mathrm{x}=6 \mathrm{\,V} \quad \therefore 1_{20\, \Omega}=\frac{6+6}{20}=0.6 \mathrm{\,A}$
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