MCQ
The value of $\frac{(32)^{0.2}+(81)^{0.25}}{(256)^{0.5}-(121)^{0.5}}$ is
- A2
- B5
- ✓1
- D11
✓
Answer
Correct option: C.
1
(c)
$\frac{(32)^{0.2}+(81)^{0.25}}{(256)^{0.5}-(121)^{0.5}}=\frac{\left(2^5\right)^{1 / 5}+\left(3^4\right)^{1 / 4}}{\left(2^8\right)^{1 / 2}-\left(11^2\right)^{1 / 2}}=\frac{2^{5 \times \frac{1}{5}}+3^{4 \times \frac{1}{4}}}{2^{8 \times \frac{1}{2}}-11^{2 \times \frac{1}{2}}}=\frac{2+3}{2^4-11}=\frac{5}{16-11}=\frac{5}{5}=1$
$\frac{(32)^{0.2}+(81)^{0.25}}{(256)^{0.5}-(121)^{0.5}}=\frac{\left(2^5\right)^{1 / 5}+\left(3^4\right)^{1 / 4}}{\left(2^8\right)^{1 / 2}-\left(11^2\right)^{1 / 2}}=\frac{2^{5 \times \frac{1}{5}}+3^{4 \times \frac{1}{4}}}{2^{8 \times \frac{1}{2}}-11^{2 \times \frac{1}{2}}}=\frac{2+3}{2^4-11}=\frac{5}{16-11}=\frac{5}{5}=1$
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